%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SEV382^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n115.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:34:07 EDT 2014

% Result   : Unknown 0.54s
% Output   : None 
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----NO SOLUTION OUTPUT BY SYSTEM
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SEV382^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n115.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 09:01:31 CDT 2014
% % CPUTime  : 0.54 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x24a2560>, <kernel.Type object at 0x24a2ab8>) of role type named a_type
% Using role type
% Declaring a:Type
% FOF formula (forall (Xr:(a->(a->Prop))) (P:(a->Prop)), (((and (forall (Xs:(a->Prop)), (((ex a) (fun (Xz:a)=> (Xs Xz)))->((ex a) (fun (Xy:a)=> ((and (Xs Xy)) (forall (Xw:a), (((Xr Xw) Xy)->((Xs Xw)->False))))))))) (forall (Xx:a), ((forall (Xy:a), (((Xr Xy) Xx)->(P Xy)))->(P Xx))))->(forall (Xx:a), (P Xx)))) of role conjecture named cTRANS_IND
% Conjecture to prove = (forall (Xr:(a->(a->Prop))) (P:(a->Prop)), (((and (forall (Xs:(a->Prop)), (((ex a) (fun (Xz:a)=> (Xs Xz)))->((ex a) (fun (Xy:a)=> ((and (Xs Xy)) (forall (Xw:a), (((Xr Xw) Xy)->((Xs Xw)->False))))))))) (forall (Xx:a), ((forall (Xy:a), (((Xr Xy) Xx)->(P Xy)))->(P Xx))))->(forall (Xx:a), (P Xx)))):Prop
% Parameter a_DUMMY:a.
% We need to prove ['(forall (Xr:(a->(a->Prop))) (P:(a->Prop)), (((and (forall (Xs:(a->Prop)), (((ex a) (fun (Xz:a)=> (Xs Xz)))->((ex a) (fun (Xy:a)=> ((and (Xs Xy)) (forall (Xw:a), (((Xr Xw) Xy)->((Xs Xw)->False))))))))) (forall (Xx:a), ((forall (Xy:a), (((Xr Xy) Xx)->(P Xy)))->(P Xx))))->(forall (Xx:a), (P Xx))))']
% Parameter a:Type.
% Trying to prove (forall (Xr:(a->(a->Prop))) (P:(a->Prop)), (((and (forall (Xs:(a->Prop)), (((ex a) (fun (Xz:a)=> (Xs Xz)))->((ex a) (fun (Xy:a)=> ((and (Xs Xy)) (forall (Xw:a), (((Xr Xw) Xy)->((Xs Xw)->False))))))))) (forall (Xx:a), ((forall (Xy:a), (((Xr Xy) Xx)->(P Xy)))->(P Xx))))->(forall (Xx:a), (P Xx))))
% % SZS status GaveUp for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
%------------------------------------------------------------------------------